To solve the problem, we need to find the probability of two independent events: rolling an odd number on the first roll of a six-sided die and rolling an even number on the second roll.
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Probability of rolling an odd number on the first roll: A six-sided die has three odd numbers: 1, 3, and 5. So, the probability of rolling an odd number is: \[ \frac{3 \text{ (odd numbers)}}{6 \text{ (total numbers)}} = \frac{1}{2} \]
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Probability of rolling an even number on the second roll: A six-sided die also has three even numbers: 2, 4, and 6. So, the probability of rolling an even number is: \[ \frac{3 \text{ (even numbers)}}{6 \text{ (total numbers)}} = \frac{1}{2} \]
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Combining the two probabilities: Since the rolls are independent, we multiply the probabilities: \[ \text{Probability of odd (first roll)} \times \text{Probability of even (second roll)} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]
Therefore, the probability of rolling an odd number on the first roll and an even number on the second roll is \(\frac{1}{4}\).
The correct response is:
1/4