To predict how many times a 3 or 5 will be rolled when rolling a 6-sided number cube 246 times, we first need to determine the probability of rolling a 3 or a 5.
There are two favorable outcomes (3 and 5) out of six possible outcomes (1, 2, 3, 4, 5, 6).
The probability \( P \) of rolling a 3 or a 5 is:
\[ P(3 \text{ or } 5) = \frac{2}{6} = \frac{1}{3} \]
Now, to find the expected number of times a 3 or a 5 will be rolled in 246 trials, we multiply the probability by the number of rolls:
\[ \text{Expected rolls of 3 or 5} = P(3 \text{ or } 5) \times \text{Number of rolls} \]
\[ \text{Expected rolls of 3 or 5} = \frac{1}{3} \times 246 \]
Calculating that:
\[ \text{Expected rolls of 3 or 5} = 82 \]
Thus, the prediction for how many times a 3 or 5 will be rolled is 82 times.