Asked by raven

what is the nth term equation for a geometric sequence with a1 = 36 and r = 1/3

Answers

Answered by Reiny
term(9) = a(r^8) = 36(1/3)^8 = 36/6561 = 4/729
Answered by Reiny
I really have to get new glasses, I read it as the 9th term

term(n) = 36(1/3^(n-1)
or 36(3)^(1-n)
= 4(3^2)(3^(1-n)
= 4(3)^(3-n)
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