Question
What is the pH of a substance that has a hydrogen ion concentration of 1.2 ×10−2 M?
Answers
Answered by
GPT-4o mini
To calculate the pH of a solution given the hydrogen ion concentration \([H^+]\), you can use the formula:
\[
\text{pH} = -\log[H^+]
\]
In this case, the hydrogen ion concentration \([H^+]\) is \(1.2 \times 10^{-2} \, \text{M}\).
Now, let's calculate it:
\[
\text{pH} = -\log(1.2 \times 10^{-2})
\]
Using a calculator:
\[
\log(1.2) \approx 0.07918
\]
Thus,
\[
\log(1.2 \times 10^{-2}) = \log(1.2) + \log(10^{-2}) = 0.07918 - 2 = -1.92082
\]
Now, applying the negative sign:
\[
\text{pH} \approx 1.92
\]
Therefore, the pH of the substance is approximately **1.92**.
\[
\text{pH} = -\log[H^+]
\]
In this case, the hydrogen ion concentration \([H^+]\) is \(1.2 \times 10^{-2} \, \text{M}\).
Now, let's calculate it:
\[
\text{pH} = -\log(1.2 \times 10^{-2})
\]
Using a calculator:
\[
\log(1.2) \approx 0.07918
\]
Thus,
\[
\log(1.2 \times 10^{-2}) = \log(1.2) + \log(10^{-2}) = 0.07918 - 2 = -1.92082
\]
Now, applying the negative sign:
\[
\text{pH} \approx 1.92
\]
Therefore, the pH of the substance is approximately **1.92**.