Question
Solve the absolute value inequality.
StartAbsoluteValue 2 x minus 2 EndAbsoluteValue greater than 8
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The solution set in interval notation is
enter your response here.
(Simplify your answer.)
B.
The solution set is empty set.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The solution set in interval notation is
enter your response here.
(Simplify your answer.)
B.
The solution set is empty set.
StartAbsoluteValue 2 x minus 2 EndAbsoluteValue greater than 8
Question content area bottom
Part 1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The solution set in interval notation is
enter your response here.
(Simplify your answer.)
B.
The solution set is empty set.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
The solution set in interval notation is
enter your response here.
(Simplify your answer.)
B.
The solution set is empty set.
Answers
Answered by
GPT-4o mini
To solve the absolute value inequality \( |2x - 2| > 8 \), we can break it down into two separate cases:
1. **Case 1**: \( 2x - 2 > 8 \)
2. **Case 2**: \( 2x - 2 < -8 \)
**Case 1**: Solve the inequality \( 2x - 2 > 8 \)
\[
2x - 2 > 8
\]
Add 2 to both sides:
\[
2x > 10
\]
Now, divide by 2:
\[
x > 5
\]
**Case 2**: Solve the inequality \( 2x - 2 < -8 \)
\[
2x - 2 < -8
\]
Add 2 to both sides:
\[
2x < -6
\]
Now, divide by 2:
\[
x < -3
\]
Now, we can combine the solutions from both cases. The overall solution set is:
\[
x < -3 \quad \text{or} \quad x > 5
\]
In interval notation, this is expressed as:
\[
(-\infty, -3) \cup (5, \infty)
\]
Thus, the solution set in interval notation is:
\[
\boxed{(-\infty, -3) \cup (5, \infty)}
\]
1. **Case 1**: \( 2x - 2 > 8 \)
2. **Case 2**: \( 2x - 2 < -8 \)
**Case 1**: Solve the inequality \( 2x - 2 > 8 \)
\[
2x - 2 > 8
\]
Add 2 to both sides:
\[
2x > 10
\]
Now, divide by 2:
\[
x > 5
\]
**Case 2**: Solve the inequality \( 2x - 2 < -8 \)
\[
2x - 2 < -8
\]
Add 2 to both sides:
\[
2x < -6
\]
Now, divide by 2:
\[
x < -3
\]
Now, we can combine the solutions from both cases. The overall solution set is:
\[
x < -3 \quad \text{or} \quad x > 5
\]
In interval notation, this is expressed as:
\[
(-\infty, -3) \cup (5, \infty)
\]
Thus, the solution set in interval notation is:
\[
\boxed{(-\infty, -3) \cup (5, \infty)}
\]