What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?(1 point) Responses 116 1/4 dm2 84 3/8 dm2 84 58 1/8 8 dm2 58 16 dm2

1 answer

To find the surface area of a rectangular prism, you can use the formula:

\[ \text{Surface Area} = 2(lw + lh + wh) \]

where \(l\), \(w\), and \(h\) represent the length, width, and height of the prism.

Given the dimensions of the rectangular prism:

  • Length \(l = 334 , \text{dm}\)
  • Width \(w = 412 , \text{dm}\)
  • Height \(h = 5 , \text{dm}\)

Now, we can calculate each area component:

  1. \(lw = 334 \times 412\)
  2. \(lh = 334 \times 5\)
  3. \(wh = 412 \times 5\)

Now, calculate each of these:

  1. \(lw = 334 \times 412 = 137768 , \text{dm}^2\)
  2. \(lh = 334 \times 5 = 1670 , \text{dm}^2\)
  3. \(wh = 412 \times 5 = 2060 , \text{dm}^2\)

Now, sum these three areas:

\[ lw + lh + wh = 137768 + 1670 + 2060 = 140498 , \text{dm}^2 \]

Now, multiply by 2 to find the surface area:

\[ \text{Surface Area} = 2 \times 140498 = 280996 , \text{dm}^2 \]

So, the surface area of the rectangular prism is 280996 dm².

Since none of the provided responses match this value, it appears there may have been an error in the problem or the options listed.