Write general conic form equation using Center: (6, -1) Radius: 10

1 answer

The general form of the equation of a circle is given by:

\[ (x - h)^2 + (y - k)^2 = r^2 \]

where \((h, k)\) is the center of the circle and \(r\) is the radius.

Given the center \((6, -1)\) and the radius \(10\), we can substitute these values into the equation:

  1. \(h = 6\)
  2. \(k = -1\)
  3. \(r = 10\)

Now substituting:

\[ (x - 6)^2 + (y + 1)^2 = 10^2 \]

Calculating \(10^2\):

\[ (x - 6)^2 + (y + 1)^2 = 100 \]

This is the equation of the circle in standard form. In general conic form (which typically takes the form \(Ax^2 + By^2 + Cx + Dy + E = 0\)), we can rearrange it:

\[ (x - 6)^2 + (y + 1)^2 - 100 = 0 \]

Expanding this equation gives us:

\[ (x^2 - 12x + 36) + (y^2 + 2y + 1) - 100 = 0 \]

Combining like terms:

\[ x^2 + y^2 - 12x + 2y - 63 = 0 \]

Thus, the general conic form of the equation is:

\[ x^2 + y^2 - 12x + 2y - 63 = 0 \]