What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?(1 point)

Responses

14
Start Fraction 1 over 4 End Fraction

2
2

1
1

12
Start Fraction 1 over 2 End Fraction

1 answer

To determine the probability of rolling an odd number on the first roll of a six-sided die (cube) and then rolling an even number on the second roll, we can break it down as follows:

  1. Rolling an odd number on the first roll: The odd numbers on a six-sided die are 1, 3, and 5. There are 3 odd numbers out of a total of 6 numbers. Thus, the probability of rolling an odd number is: \[ P(\text{odd}) = \frac{3}{6} = \frac{1}{2} \]

  2. Rolling an even number on the second roll: The even numbers on a six-sided die are 2, 4, and 6. Similarly, there are 3 even numbers out of a total of 6 numbers. Thus, the probability of rolling an even number is: \[ P(\text{even}) = \frac{3}{6} = \frac{1}{2} \]

  3. Combining the probabilities: Since the two rolls are independent, we multiply the probabilities of each event: \[ P(\text{odd on first roll and even on second roll}) = P(\text{odd}) \times P(\text{even}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]

Therefore, the final answer is: \[ \frac{1}{4} \]

So, the correct response is: Start Fraction 1 over 4 End Fraction.