To determine if there is an error in James' table, we need to analyze the combinations of marble selections for each row. Since the experiment involves selecting a marble 4 times with replacement and each marble can either be purple (P) or yellow (Y), the total number of possible outcomes is \(2^4 = 16\).
Let's examine each row and count the unique combinations:
Row 1:
- PPPP
- PPPY (listed twice)
- PPYP
Unique outcomes for Row 1: PPPP, PPPY, PPYP (3 unique combinations)
Row 2:
- PYPP
- YPPP
- PYPY
- YPYP
Unique outcomes for Row 2: PYPP, YPPP, PYPY, YPYP (4 unique combinations)
Row 3:
- YYYY
- YYYP
- YYPY
- YPYY
Unique outcomes for Row 3: YYYY, YYYP, YYPY, YPYY (4 unique combinations)
Row 4:
- PYYY
- YYPP
- PPYY
- PYYP
Unique outcomes for Row 4: PYYY, YYPP, PPYY, PYYP (4 unique combinations)
Now, let's summarize:
- Row 1 has repeated outcomes (PPPY is counted twice). This indicates that there is a mistake in this row.
- Rows 2, 3, and 4 have unique outcomes without repetition.
Thus, the row in which James made an error is:
Row 1
So, the answer is 1 (Row 1).