Use the table to answer the question.

Color
Shape Red Yellow TOTAL
Circle 12 18 30
Triangle 20 30 50
Total 32 48 80
Let event A represent the P(yellow) and let event B represent the P(yellow|triangle). Are they independent? Explain.

(1 point)
Responses

No, because both events do not include yellow.
No, because both events do not include yellow.

No, because both events do not include triangles.
No, because both events do not include triangles.

Yes, because P(A)=P(B).
Yes, because upper P left parenthesis upper A right parenthesis equals upper P left parenthesis upper B right parenthesis .

Yes, because P(A|B)=P(A).
Yes, because upper P left parenthesis upper A vertical bar upper B right parenthesis equals upper P left parenthesis upper A right parenthesis .

1 answer

To determine if events A and B are independent, we need to use the definitions of probabilities involved in these events.

Event A: \( P(\text{yellow}) \)

From the table, the total probability of yellow (across all shapes) is:

\[ P(A) = \frac{\text{Total yellow}}{\text{Overall total}} = \frac{48}{80} = 0.6 \]

Event B: \( P(\text{yellow} | \text{triangle}) \)

To find this conditional probability, we look at the number of yellow triangles and the total number of triangles:

\[ P(B) = P(\text{yellow} | \text{triangle}) = \frac{\text{Number of yellow triangles}}{\text{Total triangles}} = \frac{30}{50} = 0.6 \]

To check for independence, we need to see if:

\[ P(A|B) = P(A) \]

This means we need to find \( P(A|B) \):

Since event A does not depend directly on whether the shape is a triangle or not, we calculate \( P(A|B) \):

Event A occurs if we have any shape, and since we only consider yellow shapes in this case, we don't have a new calculation that changes depending on being a triangle.

Instead, it would be calculated as:

\[ P(A \cap B) = P(\text{yellow and triangle}) = \frac{\text{Number of yellow triangles}}{\text{Total}} = \frac{30}{80} = 0.375 \]

Now:

\[ P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.375}{0.6} = 0.625 \quad \text{(Not equal to } P(A) \text{)} \]

Now, since \( P(A|B) \neq P(A) \), the two events A and B are not independent.

The correct response here is:

No, because \( P(A|B) \neq P(A) \).