Question
If the secondary consumer in an ecosystem has 560 kcal/m2yr of energy, how much energy do the producers have?(1 point)
Responses
56,000 kcalm2yr
56,000 kcalm2yr
5.6 kcalm2yr
5.6 kcalm2yr
56 kcalm2yr
56 kcalm2yr
5,600 kcalm2yr
Responses
56,000 kcalm2yr
56,000 kcalm2yr
5.6 kcalm2yr
5.6 kcalm2yr
56 kcalm2yr
56 kcalm2yr
5,600 kcalm2yr
Answers
GPT-4o mini
In ecological energy transfer, we often use the concept of trophic levels and the 10% rule, which states that approximately 10% of the energy from one trophic level is transferred to the next level.
If the secondary consumer has 560 kcal/m²/year, to find the energy available to the producers (which is two trophic levels below the secondary consumer), we can apply the 10% rule twice:
1. From producers to primary consumers: 10% of producers' energy goes to primary consumers.
2. From primary consumers to secondary consumers: 10% of primary consumers' energy goes to secondary consumers.
Let’s denote the energy available to producers as \( P \):
1. Energy available to primary consumers = 0.1 * \( P \)
2. Energy available to secondary consumers = 0.1 * (0.1 * \( P \)) = 0.01 * \( P \)
Now we know the energy available to secondary consumers is 560 kcal/m²/year, so we can set up the equation:
0.01 * \( P \) = 560 kcal/m²/year
To find \( P \):
\( P = \frac{560 kcal/m²/year}{0.01} \)
\( P = 56000 kcal/m²/year \)
So, the energy available to the producers is **56,000 kcal/m²/year**.
If the secondary consumer has 560 kcal/m²/year, to find the energy available to the producers (which is two trophic levels below the secondary consumer), we can apply the 10% rule twice:
1. From producers to primary consumers: 10% of producers' energy goes to primary consumers.
2. From primary consumers to secondary consumers: 10% of primary consumers' energy goes to secondary consumers.
Let’s denote the energy available to producers as \( P \):
1. Energy available to primary consumers = 0.1 * \( P \)
2. Energy available to secondary consumers = 0.1 * (0.1 * \( P \)) = 0.01 * \( P \)
Now we know the energy available to secondary consumers is 560 kcal/m²/year, so we can set up the equation:
0.01 * \( P \) = 560 kcal/m²/year
To find \( P \):
\( P = \frac{560 kcal/m²/year}{0.01} \)
\( P = 56000 kcal/m²/year \)
So, the energy available to the producers is **56,000 kcal/m²/year**.