Question

Leah is playing a board game and needs to roll a 6 on a number cube two times in a row in order to win. What is the probability this will happen if she’s using a normal six-sided number cube?(1 po int)
Responses

136
Start Fraction 1 over 36 End Fraction

16
Start Fraction 1 over 6 End Fraction

12
Start Fraction 1 over 2 End Fraction

13

Answer 1

To find the probability that Leah rolls a 6 two times in a row on a normal six-sided die, we first determine the probability of rolling a 6 in a single roll.

The probability of rolling a 6 on a six-sided number cube is:

\[
P(6) = \frac{1}{6}
\]

Since the rolls are independent events, the probability of rolling a 6 two times in a row is the product of the probabilities of each roll:

\[
P(\text{two 6s}) = P(6) \times P(6) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}
\]

Therefore, the probability that Leah rolls a 6 two times in a row is:

\[
\frac{1}{36}
\]

So the correct response is:

**Start Fraction 1 over 36 End Fraction**.