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What percentage of the offspring from a monohybrid cross of two heterozygous guinea pigs will be hairless?(1 point)

Responses

25%
25%
50%
50%
75%
75%
100%

1 answer

In a monohybrid cross of two heterozygous guinea pigs (let's denote the hairless trait as "H" which is dominant and normal hair as "h"), the genotypes of the parents would be both "Hh".

The possible combinations of alleles in the offspring can be determined using a Punnett square:

        H       h
      ---------------
H  |   HH   |   Hh   |
      ---------------
h  |   Hh   |   hh   |
      ---------------

From the Punnett square, we can see the offspring will have the following genotypes:

  • 1 HH (hairless)
  • 2 Hh (hairless)
  • 1 hh (normal hair)

Therefore, the total number of hairless offspring (HH + Hh) is 3 out of 4.

To find the percentage of hairless offspring:

\[ \text{Percentage of hairless offspring} = \left(\frac{3}{4}\right) \times 100 = 75% \]

So, the answer is 75%.