Use the formula for the volume of a rectangular pyramid to find the volume of a pyramid-shaped tent whose height is 75 in., width is 111 in., and length is 111 in. when standing.(1 point)

Responses

33,034.03 in.3
33,034.03 in. cubed

308,025 in.3
308,025 in. cubed

924,075 in.3
924,075 in. cubed

400,000 in.3
400,000 in. cubed
Skip to navigation

1 answer

The formula for the volume \( V \) of a rectangular pyramid is given by:

\[ V = \frac{1}{3} \times \text{base area} \times \text{height} \]

For a rectangular base, the base area can be calculated using:

\[ \text{base area} = \text{length} \times \text{width} \]

In this case, the dimensions are:

  • Height \( h = 75 \) in.
  • Width \( w = 111 \) in.
  • Length \( l = 111 \) in.

First, let's calculate the base area:

\[ \text{base area} = l \times w = 111 , \text{in.} \times 111 , \text{in.} = 12321 , \text{in.}^2 \]

Now, we can substitute the base area and the height into the volume formula:

\[ V = \frac{1}{3} \times 12321 , \text{in.}^2 \times 75 , \text{in.} \]

Now, calculate the volume:

\[ V = \frac{1}{3} \times 12321 \times 75 = \frac{924075}{3} = 308025 , \text{in.}^3 \]

Thus, the volume of the pyramid-shaped tent is:

\[ \boxed{308,025 , \text{in.}^3} \]