Calculate the surface area of a triangular prism shaped tent if the height is 9 ft., the length is 24 ft., the width is 20 ft., and the hypotenuse of the cover is 13.45 ft.(1 point)

Responses

1,462.80 ft.2
1,462.80 ft. squared

1,215.60 ft.2
1,215.60 ft. squared

1,305.60 ft.2
1,305.60 ft. squared

982.8 ft.2

1 answer

To calculate the surface area of a triangular prism-shaped tent, we need to find the area of the two triangular bases and the three rectangular sides.

Given:

  • Height of the prism (tent) = \( h = 9 \) ft
  • Length of the prism (tent) = \( L = 24 \) ft
  • Width of the base of the triangle (prism) = \( b = 20 \) ft
  • Hypotenuse of the triangular cover = \( c = 13.45 \) ft

Step 1: Calculate the area of the triangular base

For a right triangle, the area \( A_{\text{triangle}} \) can be calculated with the formula: \[ A_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} \]

Since the width given is 20 ft and it's presumably one of the sides (the base), we assume the other side (height of the triangle) is the height of the prism. Therefore, we need the effective height of the triangle:

Identify the effective height:

Given the hypotenuse and base, we can find the height of the triangle using the Pythagorean theorem: \[ c^2 = b^2 + h^2 \ c = 13.45, , b = 20 \]

Now we need to find the height \( h \): \[ 13.45^2 = 20^2 + h^2 \ 180.6025 = 400 + h^2 \ h^2 = 180.6025 - 400 \ h^2 = -219.3975 \] There seems to be a miscalculation with our parameters because the triangle cannot be created with a base of 20 and hypotenuse of 13.45 (as it’s invalid).

Let’s assume we instead find the triangular area with the sides they are. We will assume it is equilateral for surface area calculation:

To proceed directly with the area of a triangle we use this way:

Area = (Length of the base*height)/2

Area of triangular = 
(20*9)/2 = 90

Step 2: Calculate the lateral area of the prism

The lateral area (3 rectangular sides) can be calculated with:

  1. Area of rectangle 1 (base) = base × length = \( 20 \times 24 = 480 \) ft²
  2. Area of rectangle 2 = \( \text{hypotenuse} \times L = 13.45 \times 24 \approx 322.8 \) ft²
  3. Area of rectangle 3 = \( 20 \) ft (Base) \times H (height of prism) = \( 9 \times 24 = 216 \) ft²

Thus total rectangular area = 480 + 322.8 + 216 = 1,018.8 ft²

Step 3: Calculate total surface area

The total surface area: \[ \text{Total Surface Area} = 2 \times A_{\text{triangle}} + \text{Lateral Area} \] Substituting in our known values: \[ = 2 \times 90 + 1,018.5 \ = 180 + 1,018.8 = 1,198.8 ft² \]

After careful calculations, our values should match with given options closely.

Final Answer:

None of the options match closely to calculates this domain as incorrect dimensions/a prism misalignment.

We will select the closest option to needs. The answer is effectively 982.8 ft². However, the closest to Lateral options upon triangulated dimensions evaluated 1,215.60 ft.^2 on premise

1,215.60 ft²