To find the surface area (SA) of both triangular bases of the net of the triangular prism, we can use the formula for the area of a triangle:
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]
In this case, the base of the triangle is given as 5.5 feet (the base of the triangle) and the height is 3.5 feet (the height of the triangle).
The total area for both triangular bases would be:
\[ SA = 2 \times \left( \frac{1}{2} \times \text{base} \times \text{height} \right) \]
Substituting the values we have:
\[ SA = 2 \times \left( \frac{1}{2} \times 5.5 \times 3.5 \right) \]
This simplifies to:
\[ SA = 2 \times \left( \frac{1}{2} \times 5.5 \times 3.5 \right) = 5.5 \times 3.5 \]
Thus, the correct expression for the surface area of both triangular bases is:
\[ SA = 2\left( \frac{1}{2} \right)(5.5)(3.5) \]
So, the correct response is:
\[ \text{upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 5.5 right parenthesis left parenthesis 3.5 right parenthesis} \]