What value is equivalent to log243

to the nearest thousandth? Use the change of base formula to determine your answer.(1 point)
Responses

0.817
0.817

1.332
1.332

0.184
0.184

5.426

1 answer

To find the value of \(\log_{2}(43)\) using the change of base formula, you can use:

\[ \log_{b}(a) = \frac{\log_{k}(a)}{\log_{k}(b)} \]

Where \(k\) can be any base, commonly base 10 or base \(e\). Here, we will use base 10.

Thus, we can calculate:

\[ \log_{2}(43) = \frac{\log_{10}(43)}{\log_{10}(2)} \]

Using a calculator to find these logarithmic values:

  1. \(\log_{10}(43) \approx 1.633\)
  2. \(\log_{10}(2) \approx 0.301\)

Now, substitute these values into the formula:

\[ \log_{2}(43) \approx \frac{1.633}{0.301} \approx 5.426 \]

Therefore, the value of \(\log_{2}(43)\) to the nearest thousandth is 5.426.