Asked by David


The electric flux through the surface shown in Figure Ex27.10 is 15.0 Nm2/C, and the electric field makes an angle á = 70° with the surface. What is the electric field strength? The surface is a 10cm by 10cm square.
Answered by bobpursley
E.dA is flux
E*Area*cos20=flux

check the angle. Angles are measured to the normal.
Answered by malena
120 N/C
Answered by Maddie
Flux = E*A
E = Flux/A
E = Flux/(0.1^2*cos(20))
= 1596.2667 N/c
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