To solve the system of equations using substitution, we have the following equations:
- \( y = 2x + 2 \)
- \( y = 3x + 6 \)
Since both equations are equal to \( y \), we can set them equal to each other:
\[ 2x + 2 = 3x + 6 \]
Now, we will solve for \( x \).
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Subtract \( 2x \) from both sides: \[ 2 = x + 6 \]
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Subtract \( 6 \) from both sides: \[ 2 - 6 = x \] \[ -4 = x \]
Now that we have \( x = -4 \), we can substitute this value back into one of the original equations to find \( y \). Let's use the first equation:
\[ y = 2(-4) + 2 \] \[ y = -8 + 2 \] \[ y = -6 \]
Thus, the solution to the system of equations is: \[ (x, y) = (-4, -6) \]
In coordinate form: \[ \boxed{(-4, -6)} \]