Asked by storm
A fisherman's scale stretches 3.9 cm when a 2.8 kg fish hangs from it.
(a) What is the spring stiffness constant?
N/m
(b) What will be the amplitude and frequency of vibration if the fish is pulled down 2.7 cm more and released so that it vibrates up and down?
amplitude cm
frequency Hz
(a) What is the spring stiffness constant?
N/m
(b) What will be the amplitude and frequency of vibration if the fish is pulled down 2.7 cm more and released so that it vibrates up and down?
amplitude cm
frequency Hz
Answers
Answered by
girl
a) 3.9cm = .039m
k = F/x = mg/x
= ((2.7)(9.8))/.039
= 680 N/m
k = F/x = mg/x
= ((2.7)(9.8))/.039
= 680 N/m