Use the table to answer the question.

Studying Online

This table presents the number of girls and boys who prefer or do not prefer studying online.
Girls Boys Row total
Want the option to keep studying online 10 3 13
Don’t want the option to keep studying online 5 7 12
Column total 15 10 25
Which mathematical sentence can be used to calculate the probability of selecting a student who wants the option to keep studying online or is a boy?

(1 point)
Responses

1325+1025−325
Start Fraction 13 over 25 End Fraction plus Start Fraction 10 over 25 End Fraction minus Start Fraction 3 over 25 End Fraction

325
Start Fraction 3 over 25 End Fraction

1325×1025
Start Fraction 13 over 25 End Fraction times Start Fraction 10 over 25 End Fraction

1325+1025

1 answer

To find the probability of selecting a student who either wants the option to keep studying online or is a boy, we use the formula for the probability of the union of two events.

Let:

  • A = the event that a student wants the option to keep studying online
  • B = the event that a student is a boy

According to the table:

  • Probability of A (wanting the option to keep studying online) = Number of students who want to study online / Total number of students = \( \frac{13}{25} \)
  • Probability of B (being a boy) = Number of boys / Total number of students = \( \frac{10}{25} \)
  • Probability of A and B (being both a boy and wanting to study online) = Number of boys who want the option to keep studying online / Total number of students = \( \frac{3}{25} \)

Using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

Substituting the values: \[ P(A \cup B) = \frac{13}{25} + \frac{10}{25} - \frac{3}{25} \]

Thus, the mathematical sentence that represents this calculation is: \[ \frac{13}{25} + \frac{10}{25} - \frac{3}{25} \]

Which matches with the response: Start Fraction 13 over 25 End Fraction plus Start Fraction 10 over 25 End Fraction minus Start Fraction 3 over 25 End Fraction.

So, that is the correct option.