Value 3 4 5 Total Observations 2 3 2 Charles records the number of miles he walks every day. The chart includes how many days he walked the given number of miles for one week. Calculate the standard deviation for the number of miles he walked. Round the answer to the nearest hundredth. (1 point) Responses 0.45 0.45 0.82 0.82 0.76 0.76 0.67

1 answer

To calculate the standard deviation of the miles Charles walked, we first need to determine the mean (average) of the data and then use it to find the variance and finally the standard deviation.

Step 1: Create a frequency distribution table

From the data provided:

  • 3 miles: 2 days
  • 4 miles: 3 days
  • 5 miles: 2 days

To create a frequency distribution:

| Miles (x) | Frequency (f) | |-----------|---------------| | 3 | 2 | | 4 | 3 | | 5 | 2 |

Step 2: Calculate the mean (µ)

The mean is calculated using the formula:

\[ \text{Mean} (\mu) = \frac{\sum (f \cdot x)}{\sum f} \]

Where:

  • \( f \) is the frequency
  • \( x \) is the value (miles)

Calculating \( f \cdot x \):

\[ f \cdot x = (3 \cdot 2) + (4 \cdot 3) + (5 \cdot 2) = 6 + 12 + 10 = 28 \]

Total observations (sum of frequencies):

\[ \sum f = 2 + 3 + 2 = 7 \]

Now we can calculate the mean:

\[ \mu = \frac{28}{7} = 4 \]

Step 3: Calculate variance (σ²)

The variance is calculated using the formula:

\[ \sigma^2 = \frac{\sum f (x - \mu)^2}{\sum f} \]

Calculating \( (x - \mu)^2 \):

| Miles (x) | f | x - μ | (x - μ)² | f(x - μ)² | |-----------|---|--------|----------|-----------| | 3 | 2 | 3 - 4 = -1 | 1 | 2 | | 4 | 3 | 4 - 4 = 0 | 0 | 0 | | 5 | 2 | 5 - 4 = 1 | 1 | 2 |

Now sum \( f(x - \mu)² \):

\[ \sum f(x - \mu)² = 2 + 0 + 2 = 4 \]

Now we can calculate the variance:

\[ \sigma^2 = \frac{4}{7} \approx 0.57142857 \]

Step 4: Calculate standard deviation (σ)

The standard deviation is the square root of the variance:

\[ \sigma = \sqrt{0.57142857} \approx 0.756 \]

Step 5: Round to the nearest hundredth

Rounding 0.756 to the nearest hundredth gives:

\[ \text{Standard Deviation} \approx 0.76 \]

Thus, the standard deviation for the number of miles Charles walked is 0.76.