To determine the sample space for the experiment of selecting a coin from a bag three times (with replacement) when the bag contains three types of coins (a nickel (N), a quarter (Q), and a dime (D)), we consider all possible outcomes.
Each selection can result in one of three coins (N, Q, or D), and since the selection is made three times, we can represent each outcome as a sequence of three letters, where each letter corresponds to the coin selected on that draw.
The total number of outcomes can be calculated as:
- For the first selection, you have 3 options (N, Q, D),
- For the second selection, you also have 3 options (N, Q, D),
- For the third selection, you once again have 3 options (N, Q, D).
Thus, the total number of outcomes is \(3 \times 3 \times 3 = 3^3 = 27\).
Now, we can list all the possible outcomes, which make up the sample space:
- NNN
- NNQ
- NND
- NQN
- NQQ
- NQD
- NDN
- NDQ
- NDD
- QNN
- QNQ
- QQN
- QQQ
- QQD
- QDQ
- QDN
- QDD
- DNN
- DNQ
- DQN
- DQQ
- DQD
- DDN
- DDD
- DDQ
- DND
- DNQ
So, the correct sample space is: NNN, NNQ, NND, NQN, NQQ, NQD, NDN, NDQ, NDD, QNN, QNQ, QQN, QQQ, QQD, QDQ, QDN, QDD, DNN, DNQ, DQN, DQQ, DQD, DDN, DDD, DDQ, DND, DNQ
Which can be summarized, confirming the previous exploration:
- NNN
- NNQ
- NND
- NQN
- NQQ
- NQD
- NDN
- NDQ
- NDD
- QNN
- QNQ
- QQN
- QQQ
- QQD
- QDQ
- QDN
- QDD
- DNN
- DNQ
- DQN
- DQQ
- DQD
- DDN
- DDD
- DDQ
- DND
- DNQ
This shows all \(27\) outcomes in the complete sample space.