Question
Force and Work Unit Test
5 of 125 of 12 Items
Question
A person applies 98 Newtons of force to a 20 kilogram box. They apply the force to the box over a 4-meter ramp, raising the box 2 meters from the ground. How much work is done? (1 point)
Responses
80 Joules
80 Joules
392 Joules
392 Joules
194 Joules
194 Joules
40 Joules
5 of 125 of 12 Items
Question
A person applies 98 Newtons of force to a 20 kilogram box. They apply the force to the box over a 4-meter ramp, raising the box 2 meters from the ground. How much work is done? (1 point)
Responses
80 Joules
80 Joules
392 Joules
392 Joules
194 Joules
194 Joules
40 Joules
Answers
GPT-4o mini
To calculate the work done, we can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \( \text{Force} \) is the applied force (98 Newtons),
- \( \text{Distance} \) is the distance over which the force is applied (4 meters),
- \( \theta \) is the angle between the force and the direction of the motion.
In this case, if we assume that the force is applied parallel to the ramp (which is common in such problems), the angle \( \theta \) would be \( 0 \) degrees, and thus \( \cos(0) = 1 \).
Substituting in the values:
\[ \text{Work} = 98 \, \text{N} \times 4 \, \text{m} \times \cos(0) = 98 \, \text{N} \times 4 \, \text{m} = 392 \, \text{Joules} \]
Therefore, the work done is **392 Joules**.
The correct response is:
**392 Joules**
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- \( \text{Force} \) is the applied force (98 Newtons),
- \( \text{Distance} \) is the distance over which the force is applied (4 meters),
- \( \theta \) is the angle between the force and the direction of the motion.
In this case, if we assume that the force is applied parallel to the ramp (which is common in such problems), the angle \( \theta \) would be \( 0 \) degrees, and thus \( \cos(0) = 1 \).
Substituting in the values:
\[ \text{Work} = 98 \, \text{N} \times 4 \, \text{m} \times \cos(0) = 98 \, \text{N} \times 4 \, \text{m} = 392 \, \text{Joules} \]
Therefore, the work done is **392 Joules**.
The correct response is:
**392 Joules**