Let's start by completing Part A of your question. We need to multiply the pounds of cheese by their frequency and fill in the multiplication column.
The data for orders of cheese is as follows:
-
1 / 4 pounds with frequency 4:
- Multiplication: \( 1/4 \times 4 = 1 \)
-
3 / 4 pounds with frequency 8:
- Multiplication: \( 3/4 \times 8 = 6 \)
-
1 1/4 pounds with frequency 4:
- Multiplication: \( 1.25 \times 4 = 5 \)
-
1 1/2 pounds with frequency 2:
- Multiplication: \( 1.5 \times 2 = 3 \)
Now we can summarize the completed table:
| Pounds | Frequency | Multiplication | |----------|-----------|----------------| | 1/4 | 4 | 1 | | 3/4 | 8 | 6 | | 1 1/4 | 4 | 5 | | 1 1/2 | 2 | 3 |
Now for Part B, we need to find the total number of pounds of cheese ordered. We can do this by summing the products from the multiplication column:
Total = \( 1 + 6 + 5 + 3 = 15 \)
Therefore, the total number of pounds of cheese ordered is 15 pounds.
So, the answer for Part B is:
15 pounds.