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A 3-dimensional cone is placed on top of a 3-dimensional cylinder. One of the cylinder bases is common to the cone, with the same circumference.

A 3D modeler is designing a component of a castle in a video game. She places a cone on top of a cylinder so they line up and share the same radius. The cone and the cylinder share the same height. If the volume of the cone is 50 cm^3, what is the volume of the whole object?
(1 point)

(blank) cm^3

1 answer

To find the volume of the whole object (the cone and the cylinder), we need to calculate the volume of the cylinder and then add it to the volume of the cone.

The volume \( V \) of a cone is given by the formula:

\[ V_{\text{cone}} = \frac{1}{3} \pi r^2 h \]

where \( r \) is the radius of the base and \( h \) is the height.

The volume \( V \) of a cylinder is given by the formula:

\[ V_{\text{cylinder}} = \pi r^2 h \]

In this case, we know the volume of the cone is \( 50 , \text{cm}^3 \). Setting the volume of the cone equal to the formula:

\[ 50 = \frac{1}{3} \pi r^2 h \]

From this, we can express \( \pi r^2 h \):

\[ \pi r^2 h = 150 , \text{cm}^3 \]

Now, to find the volume of the cylinder:

\[ V_{\text{cylinder}} = \pi r^2 h = 150 , \text{cm}^3 \]

Now we can find the total volume of the whole object:

\[ V_{\text{total}} = V_{\text{cone}} + V_{\text{cylinder}} = 50 , \text{cm}^3 + 150 , \text{cm}^3 = 200 , \text{cm}^3 \]

Thus, the total volume of the whole object is:

\[ \boxed{200} , \text{cm}^3 \]