To calculate the Signal-to-Noise (S/N) ratio, you can use the formula:
\[ \frac{S}{N} = \frac{\text{Signal Power}}{\text{Noise Power}} \]
Given:
- Signal power, \(S = 10 , \text{nW}\)
- Noise power, \(N = 0.1 , \text{nW}\)
Calculating the S/N ratio:
\[ \frac{S}{N} = \frac{10 , \text{nW}}{0.1 , \text{nW}} = 100 \]
Next, to convert the S/N ratio to decibels (dB), you can use the following formula:
\[ S/N \text{ (dB)} = 10 \cdot \log_{10}\left(\frac{S}{N}\right) \]
Calculating the S/N ratio in dB:
\[ S/N \text{ (dB)} = 10 \cdot \log_{10}(100) = 10 \cdot 2 = 20 , \text{dB} \]
Therefore, the Signal-to-Noise ratio is 100 and the S/N ratio in decibels is 20 dB.
Based on this calculation, the answer is:
100, 20 dB