To find \( P(A \text{ and } B) \), we need to determine the probability of both events A (on-time arrival) and B (transportation by bus) occurring together.
From the table, we can find the number of bus arrivals that were on time. The data shows:
- Number of on-time arrivals for the bus: 46
The total number of arrivals is 320.
Now we can calculate \( P(A \text{ and } B) \):
\[ P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of arrivals}} = \frac{46}{320} \]
Next, we perform the division:
\[ P(A \text{ and } B) = \frac{46}{320} = 0.14375 \]
Rounding to the nearest hundredth, we get:
\[ P(A \text{ and } B) \approx 0.14 \]
Therefore, the answer is 0.14.