To find the volume of water in a cylindrical pool filled to a depth of 5 feet, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
Where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder,
- \( h \) is the height of the water in the cylinder.
First, we need to calculate the radius of the pool. The diameter of the pool is given as 28 feet, so the radius \( r \) is:
\[ r = \frac{\text{diameter}}{2} = \frac{28}{2} = 14 \text{ feet} \]
Next, we take the height of the water \( h \) to be 5 feet (since the pool is filled to a depth of 5 feet).
Now we can substitute the values into the volume formula:
\[ V = \pi (14)^2 (5) \]
Calculating \( r^2 \):
\[ r^2 = 14^2 = 196 \]
Substituting this into the formula, we get:
\[ V = \pi (196) (5) = 980\pi \]
Using \( \pi \approx 3.14 \):
\[ V \approx 980 \times 3.14 = 3077.2 \]
Rounding to the nearest cubic foot gives us:
\[ V \approx 3077 \]
Thus, the volume of water that will be in the pool when it is filled with water to a depth of 5 feet is approximately 3077 cubic feet.
Looking at the options provided, the closest answer is:
D. 3079.