Question

Instead of charging admission to the fall​ dance, one high school required that each person bring one can of food for a local food pantry. 100 people came to the​ dance, and 49 of them brought a can of beans.
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Part 1
What is the probability that a randomly selected can of food will be beans​?
Write your answer as a fraction or whole number.
​P(beans​) ​=
  
enter your response here
Write your answer as a percent.
​P(beans​) ​=
  
enter your response here​%
Write your answer as a decimal rounded to the hundredths place.
​P(beans​) ​=
  
enter your response here

Answer 1

To find the probabilities related to the cans of food, we'll start with the information given.

1. Total number of people who brought cans: 100
2. Number of people who brought cans of beans: 49

### Part 1: Probability as a Fraction

The probability \( P(\text{beans}) \) that a randomly selected can of food will be beans is given by the formula:

\[
P(\text{beans}) = \frac{\text{Number of cans of beans}}{\text{Total number of cans}}
\]

Substituting the known values:

\[
P(\text{beans}) = \frac{49}{100}
\]

### Part 1: Probability as a Percent

To convert a fraction to a percentage, you multiply by 100%:

\[
P(\text{beans}) = \frac{49}{100} \times 100\% = 49\%
\]

### Part 1: Probability as a Decimal

To convert the fraction to a decimal, divide the numerator by the denominator:

\[
P(\text{beans}) = \frac{49}{100} = 0.49
\]

### Conclusion

- As a fraction: \( P(\text{beans}) = \frac{49}{100} \)
- As a percent: \( P(\text{beans}) = 49\% \)
- As a decimal: \( P(\text{beans}) = 0.49 \)

Here are the final answers:

1. \(\frac{49}{100}\)
2. \(49\%\)
3. \(0.49\)