huh. Just plug in the numbers. I'll do the first one...
2x^-2y^-2 for x=3 and y=-2
= 2 * 3^-2 * (-2)^-2
= 2 * 1/3^2 * 1/(-2)^2
= 2 * 1/9 * 1/4
= 1/18
These aren't as hard as they look, as long as you are careful with each step.
so, what do you get for the other one?
4. what is the value of 2x^-2y^-2 for x=3 and y=-2?
1/18
72
2(-6)^-4
1/648
5.what is the value of 1/2-2x-3y5 for x=2 and 7=-4
16
-4
-1/32
-16
1 answer