4. What is the electric potential at the surface of a gold atom’s nucleus, which is assumed to be spherical? The radius of a gold nucleus is 6.6 x 10-15 meters and the atomic number of gold is 79.
3 answers
V=kq/r q= 79*(-e)/r where e is the charge on an electron.
1.72×10^-7
V= kq/r ---------1.
k= 9*(10^9)
r= 6.6*(10^-15)m
q= ne = 79* 1.6*(10^-19)C
put these values in eq. 1.
V= 172.36 * 10^5
V= 1.7236 * 10^7 = (1.724 * 10^7)V
k= 9*(10^9)
r= 6.6*(10^-15)m
q= ne = 79* 1.6*(10^-19)C
put these values in eq. 1.
V= 172.36 * 10^5
V= 1.7236 * 10^7 = (1.724 * 10^7)V