4 to the power of 2−3⋅4+7

Answer 1

To solve the expression \( 4^{2 - 3 \cdot 4 + 7} \), follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction).

1. Start with the subtraction and multiplication inside the exponent: \[ 2 - 3 \cdot 4 + 7 \] First, calculate \( 3 \cdot 4 \): \[ 3 \cdot 4 = 12 \]

2. Now, substitute this back into the expression: \[ 2 - 12 + 7 \]

3. Calculate \( 2 - 12 \): \[ 2 - 12 = -10 \]

4. Now substitute -10 back into the expression: \[ -10 + 7 = -3 \]

Now, we have: \[ 4^{-3} \]

5. Finally, evaluate \( 4^{-3} \): \[ 4^{-3} = \frac{1}{4^3} = \frac{1}{64} \]

Thus, the final result is: \[ \frac{1}{64} \]

Answer 2

4^2-3•4+7

Answer 3

To evaluate the expression \( 4^2 - 3 \cdot 4 + 7 \), we will follow the order of operations (PEMDAS/BODMAS).

1. Calculate \( 4^2 \): \[ 4^2 = 16 \]

2. Next, calculate \( 3 \cdot 4 \): \[ 3 \cdot 4 = 12 \]

3. Now substitute these results back into the expression: \[ 16 - 12 + 7 \]

4. Perform the subtraction: \[ 16 - 12 = 4 \]

5. Finally, perform the addition: \[ 4 + 7 = 11 \]

Therefore, the final result of the expression \( 4^2 - 3 \cdot 4 + 7 \) is: \[ 11 \]