4.
The data in the table are linear. Use the table to find the slope.
TABLE:
x: 2 4 6 8
y: 1 -2 -5 -8
3/2
-3/2
-2/3
2/3
7.
Find the slope of a line that is parallel to the line containing the points (3, 4) and (2, 6). (1 point)
m = 1
m = 2
m = –2
m = 1/2
8.
Find the slope of a line that is perpendicular to the line containing the points (–2, –1) and (2, –3). (1 point)
m = –2
m = 2
m = -1/2
m = –1
My answers:
4. -2/3
7. m = –2
8. m = –1
3 answers
oh okay.......uhg i am so bad at these!
#4. Note that as x increases by 2, y decreases by 3
Since slope is (y-change)/x-change,
slope = -3/2
#7. Change in y: 2
change in x: -1
slope: -2
#8: slopes of perpendicular lines are negative reciprocals.
slope of line with points: -1/2
slope of ┴: 2
Since slope is (y-change)/x-change,
slope = -3/2
#7. Change in y: 2
change in x: -1
slope: -2
#8: slopes of perpendicular lines are negative reciprocals.
slope of line with points: -1/2
slope of ┴: 2
finally someone who doesent cus out miss sue