Let's assume the cost of 1 table is T and the cost of 1 chair is C.
From the given information, we can create two equations:
4T + 5C = $440 (equation 1)
2T = 3C (equation 2)
We can solve equation 2 for T:
T = 3C/2
Now we substitute this value in equation 1:
4(3C/2) + 5C = $440
6C + 5C = $440
11C = $440
C = $440/11
C = $40
Therefore, the cost of 1 chair is $40. Answer: \boxed{40}.
4 tables & 5 chairs cost $440. The cost of 2 tables is the same as the cost of 3 chairs. How much is 1 chair?
1 answer