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Question

Question
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses

92+16x=104+13x ; x=6
92 plus 16 x equals 104 plus 13 x ; x equals 6

92−16x=104−13x ; x=−4
92 minus 16 x equals 104 minus 13 x ; x equals negative 4

92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4

104+16x=92+13x ; x=4
104 plus 16 x equals 92 plus 13 x ; x equals 4
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Answer 1

To solve this problem, we need to set up an equation where the number of cans filled by the first machine is equal to the number of cans filled by the second machine.

Let x be the number of minutes it takes for the two machines to have filled the same number of cans.

For the first machine: number of cans filled = 92 + 16x
For the second machine: number of cans filled = 104 + 13x

Setting these two expressions equal to each other, we get:
92 + 16x = 104 + 13x

Now, we can solve this equation to find the value of x.

Subtract 13x from both sides:
92 + 3x = 104

Subtract 92 from both sides:
3x = 12

Divide both sides by 3:
x = 4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.