4 of 54 of 5 Items

4 of 54 of 5 Items
Question
A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)
Responses

7.5 N
7.5 N

0.01 N
0.01 N

6.5 N
6.5 N

1 N

2 answers

The force exerted on the ball can be calculated using the formula F = ma, where F is the force, m is the mass of the ball, and a is the acceleration.

First, we need to convert the velocity of the racket from kilometers per hour to meters per second:

65 km/hour = 18.06 m/s

Next, we can use the formula d = 1/2at^2 to find the time it takes for the ball to hit the floor. We know that the initial velocity of the ball is 18.06 m/s and the acceleration is 10 m/s^2. The distance the ball travels is the length of the tennis court, which is typically 23.77 meters for a singles match.

23.77 = 1/2(10)t^2

t^2 = 4.754

t = 2.18 seconds

Now we can use the formula v = at to find the velocity of the ball when it hits the floor.

v = 10 x 2.18 = 21.8 m/s

Finally, we can use the formula F = ma again to find the force exerted on the ball by the floor. The mass of the ball is 0.1 kg and the acceleration is 10 m/s^2.

F = 0.1 x 10 = 1 N

Therefore, the answer is 1 N.
what a lot of work!
As always, F=ma.
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