the prob you will pick a correct first number = 4/10
the prob that the second one is correct = 3/9
etc
so the prob of drawing a 1,2,3, and 4
= (4/10)(3/)(2/8)(1/7) = 1/210
or
total number of ways of 'choosing' 4 specifics form 10 is C(10,4) = 210
only one of these will be the correct choice we want.
so prob = 1/120
4 numbers are drawn at random from 10 tiles numbered 0-9. what are the odds of drawing numbers 1-4 in any order.
the question is confusing me
3 answers
line << = (4/10)(3/)(2/8)(1/7) = 1/210 >>
should read
= (4/10)(3/9)(2/8)(1/7) = 1/210
and it looks like a transposed the digits in the last line
so prob = 1/210
should read
= (4/10)(3/9)(2/8)(1/7) = 1/210
and it looks like a transposed the digits in the last line
so prob = 1/210
Odds are different from probability, therefore, the odds would be 1:9 for each one. You can only pull a 2 out of the bag of 9 different tiles once. Same goes for the rest of the numbers.
2 answers