4 NH3 + 5 O2 --> 4 NO + 6 H2O.

How many grams of O2 are required to product 90 g of NO?

Please assist in solving.

4 answers

Convert 90 g NO to mols NO. #mols = grams/molar mass.

Convert mols NO to mols O2 using the coefficients in the balanced equation.

Convert mols O2 to grams O2.
grams O2 = mols O2 x molar mass O2.
Still lost. How do you convert mols NO to mols O2?
Use the coefficients in the balanced equation. It's just the usual dimensional kind of problem.
mols O2 = mols NO x (5 mols O2/4 mols NO) = ??
Note that the numbers come from the coefficients. Note that we know which material to put on the top and bottom by choosing those that will make the unit come out right. For example, see the mols NO cancel (that's the unit we DOM'T want) and it leaves mols O2 for the unit (and that's the unit we DO want to convert to). So all that conversion does is to convert from mols O2 to mols NO.
Put in brief form, it is
mols O2 = mols NO x factor and there are only two ways to write the factor. One way is as above (5 mols O2/4 mols NO) and the other way is 4 mols NO/5 mols O2). So how do you know NOT to write
mols O2 = mols NO x (4 mols NO/5 mols O2)?? Because the units won't cancel. In fact, the unit would NOT be mols O2 (which we want) but mols NO^2/mols O2.
I hope this helps.
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