4 mols of NH3 for every 3 of O2
so 4
4/3 = 8/6
so 6 of O2
also 4/2 = 8/4 so 4 of N2
4/6 = 8/12 so 12 of H2O
I am getting bored :(
4/2 = 2/1 so 2 of NH3
3 of H2O
enough already
4 NH3 + 3 O2 --> 2 N2 + 6 H2O
a.) Assume 3.0 mol O2 completely reacts. Calculate the moles required for the other reactant. Calculate the moles that can be produced for each product.
b.) Assume 8.0 mol NH3 completely reacts. Calculate the moles required for the other reactant. Calculate the moles that can be produced for each product.
c.) Assume 1.0 mol N2 is produced. Calculate the moles required for each reactant. Calculate the moles that can be produced for the other product.
d.) Assume 0.40 mol H20 is produced. Calculate the moles required for each reactant. Calculate the moles that can be produced for the other product.
How do you do this?
1 answer