4^log16 7
= (16^(1/2))^log16 7
= (16)^((1/2))^log16 7)
= 16^log16 sqrt(7)
recall the property that
a^loga k = k
16^log16 sqrt(7)
= sqrt(7)
or , using your calculator
4^log16 7
= 4^(log7/log16)
= 4^.70183873
= 2.645751309 and sqrt(7) = 2.645751311
not bad
4^log16 (7)
the base of the log is 16. 4 is being raised to the entire log16 (7).
show all steps please!
1 answer