On my screen your intended symbol did not show up correctly.
did you mean:
ln e = ln (√3/(x) ) - 4ln e ?
if so, then
5ln e = ln (√3/x)
ln e^5 = ln (√3/x)
anti-ln it
e^5 = √3/x
x = √3/e^5
Let me know if your equation was meant differently.
4 In e= In (�ã(3))/(x)-4 In e Solve the equations by finding the exact solution.
4 answers
Thank you for answering my question.But I really do not know what happend to the 4 in front of the equation?
ahh, my error, I thought it was question #4
easy to fix
4 ln e = ln (√3/(x) ) - 4ln e
8ln e = ln (√3/x)
ln e^8 = ln (√3/x)
anti-ln it
e^8 = √3/x
x = √3/e^8
easy to fix
4 ln e = ln (√3/(x) ) - 4ln e
8ln e = ln (√3/x)
ln e^8 = ln (√3/x)
anti-ln it
e^8 = √3/x
x = √3/e^8
Thank you for your help.