4 csc 2x = 2 csc2 x tan x

1 answer

I read that as
4csc(2x) = (2csc^2 x)(tanx)

LS = 4/cos (2x)
= 4/(2sinxcosx)
= 2/(sinxcosx)

RS = (2/sinx)((1/sinx)(sinx/cosx)
= 2/(sinxcosx)
= LS
Similar Questions
  1. Find the derivative ofy=cot³(1-2x)² y'=3[cot(1-2x)²]² (-csc²(1-2x)²)(2-4x)(-2) y'=(-6+24x)[cot(1-2x)²]²(-csc²(1-2x)²)
    1. answers icon 2 answers
  2. Someone please help!!!?7. What is 1/cot(x) in terms of sine? This is what I've got so far: sin = 1/csc tan = 1/cot 1+cot2(x) =
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Can you draw the ans. To make it clear to me , please?Establish identity: tan∅ + cot∅ -------------- = csc²∅ tan∅
    1. answers icon 1 answer
more similar questions