Let \( t_C \) be the time (in hours) that Carlos drove, and \( t_M \) be the time (in hours) that Maria drove.
From the problem, we know the following:
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The total time driven by both is: \[ t_C + t_M = 3.8 \]
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The total distance driven is 191 miles, which can be expressed using their average speeds: \[ 49t_C + 52t_M = 191 \]
Now we have a system of two equations:
- \( t_C + t_M = 3.8 \)
- \( 49t_C + 52t_M = 191 \)
We can solve for \( t_C \) in terms of \( t_M \) using the first equation: \[ t_C = 3.8 - t_M \]
Now, substitute \( t_C \) in the second equation: \[ 49(3.8 - t_M) + 52t_M = 191 \]
Distributing \( 49 \): \[ 186.2 - 49t_M + 52t_M = 191 \]
Combine like terms: \[ 186.2 + 3t_M = 191 \]
Now, isolate \( t_M \): \[ 3t_M = 191 - 186.2 \] \[ 3t_M = 4.8 \] \[ t_M = \frac{4.8}{3} = 1.6 \]
Therefore, Maria drove for approximately \( 1.6 \) hours.
Rounding to the nearest tenth, Maria drove for \( \boxed{1.6} \) hours.