T=0⁰C = 273 K,
p= 1.01325•10⁵ Pa,
M=(12+16+16) •10³ = 40•10³ kg/mol.
V=mRT/Mp=
= 0.004•8.31•273/44•10⁻³•1.01325•10⁵=
=0.00204 m³= 2.04 L
4.4 g of CO2 contains how many liters of CO2 at STP ?
a) 2.4 litre b) 2.24 litre
c) 44 Litre d) 22.4 litre
2 answers
2.4