To solve the equation \(-\frac{4}{3}x + 2 = 10\), follow these steps: 1. **Isolate the term with \(x\)** by subtracting 2 from both sides: \[ -\frac{4}{3}x = 10 - 2 \] \[ -\frac{4}{3}x = 8 \] 2. **Eliminate the negative coefficient of \(x\)** by multiplying both sides by -1: \[ \frac{4}{3}x = -8 \] 3. **Multiply both sides by the reciprocal of \(\frac{4}{3}\)**, which is \(\frac{3}{4}\): \[ x = -8 \cdot \frac{3}{4} \] \[ x = -6 \] So, the solution is: \[ x = -6 \]

−4/3 x+2=10

1 answer

To solve the equation \(-\frac{4}{3}x + 2 = 10\), follow these steps:

Isolate the term with \(x\) by subtracting 2 from both sides:

\[ -\frac{4}{3}x = 10 - 2 \]

\[ -\frac{4}{3}x = 8 \]
Eliminate the negative coefficient of \(x\) by multiplying both sides by -1:

\[ \frac{4}{3}x = -8 \]
Multiply both sides by the reciprocal of \(\frac{4}{3}\), which is \(\frac{3}{4}\):

\[ x = -8 \cdot \frac{3}{4} \]

\[ x = -6 \]

So, the solution is:

\[ x = -6 \]