To determine which system of equations has (4, -3) as a solution, you can substitute \(x = 4\) and \(y = -3\) into multiple equations and see which system yields true statements.
Let's create a few sample equations:
- \(y = 2x - 11\)
- \(y = -x + 1\)
Substituting into the first equation: \[ -3 = 2(4) - 11 \ -3 = 8 - 11 \ -3 = -3 \quad \text{(True)} \]
Substituting into the second equation: \[ -3 = -4 + 1 \ -3 = -3 \quad \text{(True)} \]
Both equations are satisfied with (4, -3).
Thus, the system of equations:
- \(y = 2x - 11\)
- \(y = -x + 1\)
has (4, -3) as a solution.
You can create any number of systems with the same point by modifying coefficients or constants, but the above example serves to illustrate the concept. If you have specific equations in mind, please provide them for verification.