To determine which system the point \((4, -3)\) is a solution for, we can substitute \(x = 4\) and \(y = -3\) into each equation in the systems provided.
Let's evaluate each option:
Option 1:
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Equation 1: \(7x + 9y = 55\) \[ 7(4) + 9(-3) = 28 - 27 = 1 \quad (\text{not } 55) \]
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Equation 2: \(3x - 9y = -15\) \[ 3(4) - 9(-3) = 12 + 27 = 39 \quad (\text{not } -15) \]
Option 2:
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Equation 1: \(7x + 9y = 55\) \[ 7(4) + 9(-3) = 28 - 27 = 1 \quad (\text{not } 55) \]
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Equation 2: \(3x + 9y = -15\) \[ 3(4) + 9(-3) = 12 - 27 = -15 \quad (\text{true}) \]
Option 3:
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Equation 1: \(7x - 9y = 55\) \[ 7(4) - 9(-3) = 28 + 27 = 55 \quad (\text{true}) \]
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Equation 2: \(3x - 9y = -15\) \[ 3(4) - 9(-3) = 12 + 27 = 39 \quad (\text{not } -15) \]
Option 4:
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Equation 1: \(7x - 9y = 55\) \[ 7(4) - 9(-3) = 28 + 27 = 55 \quad (\text{true}) \]
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Equation 2: \(3x + 9y = -15\) \[ 3(4) + 9(-3) = 12 - 27 = -15 \quad (\text{true}) \]
Conclusion:
The correct option where \((4, -3)\) is a solution to both equations is:
7x−9y=55 and 3x+9y=−15 (Option 4).