y^2 + 8y +24x -32 = 0
y^2 + 8y +16 +24x -48 = 0
[y -(-4)]^2 = -24(x-2)
k = -4
p = -6
h = 2
3y^2+24y+72x-96=0
Can anyone put this in standard form: (y - k)2 = 4p(x - h)
All help is greatly appreciated! :)
1 answer