To solve the system of equations using elimination, we need to eliminate one of the variables by adding or subtracting the equations.
Let's start by multiplying the first equation by 8 and the second equation by 3 to make the coefficients of y in both equations the same:
(8)(3x+y) = (8)(20)
(3)(8x-y) = (3)(46)
This simplifies to:
24x + 8y = 160
24x - 3y = 138
Now, we can subtract the second equation from the first equation:
(24x + 8y) - (24x - 3y) = 160 - 138
24x - 24x + 8y + 3y = 22
11y = 22
Divide both sides of the equation by 11 to solve for y:
y = 2
Plug this value back into one of the original equations to solve for x. Let's use the first equation:
3x + 2 = 20
3x = 18
x = 6
The solution to the system of equations is x = 6 and y = 2.
3x+y=20
8x-y=46
Use elimation
1 answer